Math, asked by khushishukla9876, 1 year ago

what length of tarpaulin 3M wide will be required to make conical tent of 8 metre and base radius 6 m ? assume that the extra length of the material that will be required for stitching machines and wasting in cutting is approximately 20cm ( use pi = 3.14 )

Answers

Answered by shubh1729
15
radius of conical tent=6m
height of conical tent=8m
slant height=√r²+he
=√6²+8²
=√36+64
=√100
=10m
CSA=I'll
=3.14*6*10
=3.14*6
=188.4m
width of cloth=3m
length of cloth=188.4/3
=62.8m
extra cloth=20cm
=0.2m
total length of cloth=62.8+0.2
=63m
please mark this answer as brainlist.

babu4211: how like 0.2 came
eitish: 3.14*6*10
eitish: =31.4*6
shubh1729: by changing it into metre
shubh1729: please mark my answer as brainiest
eitish: sorry
shubh1729: why
Answered by manjumadhavva
5

Answer: h=8m

r=6m

l²= h²+r²

l²=8²+6²

l²=64+36

l²=100

l=10m


CSA = πrl

=3.14×6×10

=187.4cm²


The length of materials is approx 20 cm that is 0.2m


l=0.2

w=3m

area of sheet= area of tent

l×b=πrl

0.2×3m=188.4m²

0.2=188.4m²/3m

0.2=62.8m²

=62.8-0.2

=62.6(round off it)

l=63m


:. The length of tarpaulin is 63m.


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