what length of tarpaulin 3M wide will be required to make conical tent of 8 metre and base radius 6 m ? assume that the extra length of the material that will be required for stitching machines and wasting in cutting is approximately 20cm ( use pi = 3.14 )
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Answered by
15
radius of conical tent=6m
height of conical tent=8m
slant height=√r²+he
=√6²+8²
=√36+64
=√100
=10m
CSA=I'll
=3.14*6*10
=3.14*6
=188.4m
width of cloth=3m
length of cloth=188.4/3
=62.8m
extra cloth=20cm
=0.2m
total length of cloth=62.8+0.2
=63m
please mark this answer as brainlist.
height of conical tent=8m
slant height=√r²+he
=√6²+8²
=√36+64
=√100
=10m
CSA=I'll
=3.14*6*10
=3.14*6
=188.4m
width of cloth=3m
length of cloth=188.4/3
=62.8m
extra cloth=20cm
=0.2m
total length of cloth=62.8+0.2
=63m
please mark this answer as brainlist.
babu4211:
how like 0.2 came
Answered by
5
Answer: h=8m
r=6m
l²= h²+r²
l²=8²+6²
l²=64+36
l²=100
l=10m
CSA = πrl
=3.14×6×10
=187.4cm²
The length of materials is approx 20 cm that is 0.2m
l=0.2
w=3m
area of sheet= area of tent
l×b=πrl
0.2×3m=188.4m²
0.2=188.4m²/3m
0.2=62.8m²
=62.8-0.2
=62.6(round off it)
l=63m
:. The length of tarpaulin is 63m.
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