Question

what length of tarpaulin 3m wide will be required to make a conical tent of hieght 8m nd base radius 6m? Assume that the extra length of material that will be required for stichching margins nd wastage in cutting is approximately 20m (π=3.14)​..

Answer 1

Answer:

Step-by-step explanation:

Radius of the base (r) = 6 m

Height of the conical tent (h) = 8 m

Let l be the slant height of the cone.

∴ l = √h2 + r2 

⇒ l = √82 + 62 

⇒ l = √100 

⇒ l = 10 m

CSA of conical tent = πrl

                                = (3.14 × 6 × 10) m2 = 188.4 m2

Breadth of tarpaulin = 3 m

Let length of tarpaulin sheet required be x.

20 cm will be wasted in cutting.

So, the length will be (x - 0.2 m)

Breadth of tarpaulin = 3 m

Area of sheet = CSA of tent

[(x - 0.2 m) × 3] m = 188.4 m2

⇒ x - 0.2 m = 62.8 m

⇒ x = 63 m

Answer 2

Heya buddy

Here is your answer

Just check the attached