what length of tarpaulin 3m wide will be required to make a conical tent of hieght 8m nd base radius 6m? Assume that the extra length of material that will be required for stichching margins nd wastage in cutting is approximately 20m (π=3.14)..
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Given:
length of tarpaulin= 3m
height of tent=8m
base radius =6m
According to question
Answer:
Here h = 6 m, r = 8 m
We have, l = √(r2 + h2)
= √(62 + 82)
= √(36 + 64)
= √100
=> l = 10 m
Curved surface area of the tent = πrl
= 3.14 * 6 * 10
So, required length of tarpaulin = (3.14 * 6 * 10)/3 m + 20 cm
= (3.14 * 2 * 10) m + 20 cm
= 62.8 + 0.2 m
= 63 m
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