What mas of H2 will react with 22.4 litre 02 to produce 36 gram of water?
Answers
Given:
22.4L of O2 is reacting with H2 to form H20 (Water)
To Find:
The mass of H2 required for the reaction to complete.
Procedure:
1) Chemical Reaction:
2H2+O2 -----> 2H2O
2) 1 Mole of any compound implies 22.4L of Volume ( according to STP conditions) Consider the mass of Oxygen as 16 and Hydrogen as 1 .
3)The Molecular weight of water (H20) is 18 . Therefore mass of 2 moles of Water is 36.
4) From the chemical equation we can conclude that, 36grams of water requires 2 moles of Hydrogen ( Following law of proportion of mass which states the sum of the atomic weights of the compounds of reactants side are same as the sum of the atomic weights of the compounds of the products side)
5) Therefore 2 moles of H2 is used for the reaction to provide 36g of H2O.
6) Mass of 2H2 is 4* (mass of hydrogen atom) i.e , 4*1 =4.
(Since 2H2 implies a total of 4 molecules of Hydrogen atom)
Therefore 4 grams of H2 is reacted with O2 to form 36g of water (H20)