Question

What mass of ammonia (NH3) gas will have the same number of molecules as 11g of carbon dioxide gas (N=14 u, H=1 u, C=12u, O=16 u).

Answer 1

No of molecules=(given mass/molar mass)× avogadro no

No of moles in carbon dioxide=(11/44 )×6.022×10²³ (CO2=12+2×16=44)

No of mole in CO2=(1/4)6.022×10²³



No of molecules in NH3=(unknown mass/17)×6.022×10²³

Since same no of molecules
(1/4)×6.022×10²³=(unknown mass/17)×6.022×10²³ (avogadro number canceled from boh sides)

By cross multiplying we can get the value of unknown mass as
Unknown mass=17/4= 4.25gm

Answer 2

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