Chemistry, asked by krishanggupta333, 2 months ago

What mass of Barium chloride is required to react with 48.6 grams of sodium phosphate according to the following reaction: 2 Na3PO4 + 3BaCl2 → Ba3(PO4)2 + 6 NaCl​

Answers

Answered by 125sari
1

Answer: 92.6 g of BaCl2

Explanation:

The answer is 92.6 g of BaCl 2

Answered by ganeshgani1432m
0

Answer:

Nooooooooo oo not the answer so sorry

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