Question

What mass of barium chloride would be decomposed by 9.8 g of sulphuric acid, if 12g of barium sulphate & 2.75g of produced in a hydrogen chloride were produced in a reaction assuming that the law of conservation of mass is true?

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Answer 1

Hello dear!

Let the mass of barium chloride be M.

From the question, we will get the following equation:

BaCl₂ + H₂SO₄ → BaSO₄ + 2HCl

∵ We are assuming that the law conservation of mass is true.

So, total mass of reactants = total mass of products

∴ M  + 9.8 = 12 + 2.75

M = 14.75 - 9.8

M = 4.95 g

Hence, mass of barium chloride is 4.95 g.

Answer 2

According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants

For the chemical reaction: NaCl + H2SO4 NaHSO4 + HCI

Mreactant = mproducts

m Naci + mH, SO4 = MNAHS0, + MHCI

... x + 9.8 = 12 + 2.75

.'. x = 4.95 g

Hence, mass of barium chloride is 4.95 g.

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