what mass of Ca will have the same number of atoms as in 3.2 g of S (ans:- 4g)
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We know that,
Weigh of 1 mole of an element = Atomic mass of the element
Number of atoms in 1 mole of an element = 6.023 x1023.
So, 32 g of S contains 6.023x1023 atoms.
Therefore, 3.2 g of S will contain ( 6.023x1023x 3.2)/32 = 6.023x1022 atoms of S.
Now, weight of 6.023x1023 atoms of Ca is 40 g.
Thus, weight of 6.023x1022 atoms of Ca will be ( 6.023x1022 x 40) / 6.023x1023 = 4 g.
Weigh of 1 mole of an element = Atomic mass of the element
Number of atoms in 1 mole of an element = 6.023 x1023.
So, 32 g of S contains 6.023x1023 atoms.
Therefore, 3.2 g of S will contain ( 6.023x1023x 3.2)/32 = 6.023x1022 atoms of S.
Now, weight of 6.023x1023 atoms of Ca is 40 g.
Thus, weight of 6.023x1022 atoms of Ca will be ( 6.023x1022 x 40) / 6.023x1023 = 4 g.
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