What mass of carbon dioxide (CO2) will contain 3.011 x 10^23 molecules?
Answers
Answer:
22 grams
Explanation:
No.of mole=no.of the molecules/Avogadro no.
n=no.of mole
n=3.011*10^23/6.022*10^2
n=0.5 mole
no.of mole.=mass/molecular mass
molecular mass of CO2=C-12g;O2-16*2-32=12+32g=44g
m(mass)=0.5mole*44g=22g
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Given: carbon dioxide (CO2) contain 3.011 x 10^23 molecules
To find: Mass of carbon dioxide
Solution: we are given that Carbon Dioxide contains 3.011 x 10^23 molecules and we need to find its mass for which we have a formula that is
n= N/NA
here n is the number of moles, N is the number of molecules and NA is Avogadro's Number having its value of 6.022×10^23
on putting values we will get
n = 0.5 mol
now we know that
n = m/M
here n is the number of moles, m is the mass of that substance, M is the molecular mass of that substance
here we are given carbon dioxide which has a molecular mass of 44gms
on putting values we get
m = 0.5×44 = 22gms
Therefore, the mass of carbon dioxide (CO2) that will contain 3.011 x 10^23 molecules is 22 gms.