Physics, asked by ShikharB2353, 1 year ago

What mass of copper deposited in one hour by a current of 1.62 a?

Answers

Answered by Anonymous
3
We first write the electrode equation for deposit of copper at the cathode.

Cu²⁺ + 2e==>Cu₍s₎

This implies that 2 moles of electrons produce one mole of copper. 

Given time and current we can calculate the charge of the electrons:

Q =It where Q is the charge in Coulombs, I is the current in amperes and t the time in seconds.

Q is thus: 60 × 60 × 1.62=3600 × 1.62=5832Coulombs.

1mole of an electron = 96500Coulombs

5832/96500=0.060435moles

2 moles of electrons produce 1 mole of copper thus the moles of copper deposited are:

0.060435/2 = 0.030218 moles

Mass of copper deposited = moles of copper × atomic mass of copper.

Atomic mass of copper =63.5g

63.5 × 0.030218=1.9182g


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