What mass of he gas occupies 8.5 liters at 0c and 1 atmosphere? (the molar mass of he = 4.00 g/mol.)?
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Answered by
1
The condition of NTP is given:
At NTP 1 mole of gas occupies 22.4L of volume..
So, 8.5/22.4= 0.379 moles
0.379*4=1.51 grams
Hope its the ryt ans..
At NTP 1 mole of gas occupies 22.4L of volume..
So, 8.5/22.4= 0.379 moles
0.379*4=1.51 grams
Hope its the ryt ans..
Answered by
0
1atm(8.5L)=n(.08206Latm/moleK)(273K), n=.3794mole, m=.3794mole(4g/mole)=1.52g
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