Question

What mass of iron is formed when 240 g of iron(III) oxide reacts with carbon monoxide?
Fe²0³ + 3C0 - 2Fe + 3C0²​

Answer 1

Answer :- 168 g Fe

• $\bf\red{ \: Fe_{2}O_{3} + 3 CO \rightarrow 2 Fe + 3 CO_{2} }$

• $\bf \: 160 \: g \: \: Fe_{2}O_{3} \implies 2 × 56 g \: \: Fe$

• $\bf \: 240 \: \: g \: \: Fe_{2}O_{3} \implies x \: \: g \: \: Fe$

• $\bf \: x = \frac{2×56×240}{160}$

• $\bf x = 168 \: g \: Fe$

Answer 2

Explanation:

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