What mass of KMnO4 should you use to prepare 1 litre of a 3g/L
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Given values:
Molarity=1.5
Volume of solution=1 L
Lets find No of moles of KMnO₄:
1.5= No of moles of KMnO₄/1
No of moles=1.5
Moles=given mass/Molar mass
Molar mass of KMNO₄=158
Here we need to find the given mass
1.5=given mass/158
given mass=1.5×158
=237g
Hence we require 237 g of KMnO₄ to make a solution of 1.5 M
saleimanului:
How do you came up with 1.5 M
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