Question

what mass of MgSo4.7H2o do you require to make 150ml of 10M solution​

Answer 1

Explanation:

Magnesium sulfate-7-water, MgSO4. 7H2O, crystals are obtained by evaporation. They may be recrystallised to increase purity. You can make magnesium sulfate-7-water in the laboratory by reacting magnesium oxide with dilute sulfuric acid.

Answer 2

Answer:

You will need a mass of 2.45g of MgSO4.7H2O to make a 10M solution of 150ml.

Explanation:

From the above question,

They have given :

To make a 10 M solution of Magnesium Sulfate heptahydrate (MgSO4.7H2O), we need to know the number of moles of MgSO4.7H2O required to make 150 mL of solution.

This can be calculated using the following formula:

M = moles of solute / liters of solution

where M is the molarity (10 M in this case), and moles of solute is equal to volume * molarity.

So,

     We can calculate the number of moles of MgSO4.7H2O as follows:

moles of MgSO4.7H2O = 150 mL * 10 M

                                       = 1.5 moles

The formula weight of MgSO4.7H2O is 246.48 g/mol. So, we can calculate the mass of MgSO4.7H2O required as follows:

mass of MgSO4.7H2O

                      = moles of MgSO4.7H2O * formula weight of MgSO4.7H2O

                      = 1.5 moles * 246.48 g/mol

                      = 367.72 g

Therefore, to make 150 mL of 10 M solution of MgSO4.7H2O, we need 367.72 g of MgSO4.7H2O.

               Molar mass = 246.47g/mol

Then, you must use the amount of liters to solve for the moles:

Moles of MgSO4.7H2O = liters of solution (150ml) x molarity (10M)

Finally,

          Use the moles to calculate the mass of MgSO4.7H2O:

Mass of MgSO4.7H2O = moles of MgSO4.7H2O x molar mass

Therefore,

             You will need a mass of 2.45g of MgSO4.7H2O to make a 10M solution of 150ml.

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