Question

What mass of oxygen is required to react completely with 24 g of CH4 in the following reaction? CH4 (g) + 2O2 (g) → CO2 (g) + 2H2 O(1)

Answer 1

Answer:

See, if you observe carefully, then you can see that 1 mole CH4 requires 2 mole of oxygen molecule to release 1 mole CO2 and 2 moles of H20.

Given,

24g of CH4

We know 1 mole of CH4 is = 12+4*1 =16g

Moles of CH4 present in the equation is= Given mass

Molar mass

i.e. 24/16=1.5mol

Therefore, moles of oxygen in the reaction is 2 times the mole in CH4 i.e 2*1.5=3mol.

Now we know,

1 mole oxygen= 16g

3 mole= 16*3 = 48g

Therefore, 48g of oxygen is required to react completely with 24g of CH4.

Hope it helps you.

Answer 2

Answer:

48 Gram or 3 Moles of oxygen

Explanation:

CH4 + 2O2 = CO2 + 2H20

1mol + 2mol =  1mol + 2mol

16gram + 32gram = 44gram + 36gram

16 gram CH4 reacts with 32 gram Oxygen

24 gram CH4 reacts with 32/16 x 24 gram oxygen

Hence, 24 gram CH4 reacts with 48 gram Oxygen i.e. 3 moles