Question

Calculate the weight of 60 % sulphuric acid required to decompose 150 g of chalk (calcium carbonate). Given Ca = 40, C = 12, O = 16, S = 32)

Answer 1

Answer:

88.2

Explanation:

100g of CaCO3 is decomposition by = 98 g of H2SO4

150 g of CaCO3 is decomposed by = 98*150/100=147

Mass of H2SO4= 60*147/100

=88.2g

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