What mass of potassium chloride would be needed to form a saturated solution in 50 gram of water at 313 ke given the solubility of the salt 40 gram 100 by 100 gram of water at this temperature?
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Answered by
22
Answer:
solubility=40g
solvent=50
let solute=x g
solubility=( mass of solute/ mass of solvent) 100
=40 multiply by x/50 divided by 100
=40=x/2
=40/2=x
=20g
Answered by
3
Given:
Solubility of the salt = 40g/100g
Solvent (water) = 50g
Temperature = 313k
To find:
Mass of Potassium chloride (solute)
Solution:
Solubility = (Mass of solute / mass of solvent) × 100
Let mass of potassium chloride (solute) be 'x'g.
We get,
- 40 = (x/50)×100
- x = 20g.
Therefore, the mass of potassium chloride will be 20gm.
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