Question

What mass of potassium chloride would be needed to form a saturated solution in 50 gram of water at 313 ke given the solubility of the salt 40 gram 100 by 100 gram of water at this temperature?

Answer 1

Answer:

solubility=40g

solvent=50

let solute=x g

solubility=( mass of solute/ mass of solvent) 100

=40 multiply by x/50 divided by 100

=40=x/2

=40/2=x

=20g

Answer 2

Given:

Solubility of the salt = 40g/100g

Solvent (water) = 50g

Temperature = 313k

To find:

Mass of Potassium chloride (solute)

Solution:

Solubility = (Mass of solute / mass of solvent) × 100

Let mass of potassium chloride (solute) be 'x'g.

We get,

• 40 = (x/50)×100
• x = 20g.

Therefore, the mass of potassium chloride will be 20gm.