What mass of sodium is contained in 53g of sodium carbonate
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Answered by
29
molecular weight of Na2CO3 is 106g (23×2+12+16×3).
It contains 23×2=46g Na.
Since 106g Na2CO3 contains 46g Na,
so 53g Na2CO3 will contain
(46×53)/106 g Na
=23g Na.
Hope you got it.
It contains 23×2=46g Na.
Since 106g Na2CO3 contains 46g Na,
so 53g Na2CO3 will contain
(46×53)/106 g Na
=23g Na.
Hope you got it.
Answered by
1
you can get the answer from attachment
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