Question

what mass of sodium reacts with 95g of titanium chloride

Answer 1

Answer:

46 gram

Explanation:

46 gram of Na react with Ticl3 to form Nacl

Answer 2

The mass of sodium needed to react is 47.56 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$     .....(1)

Given mass of titanium chloride = 95 g

Molar mass of titanium chloride = 189.7 g/mol

Putting values in equation 1, we get:

$\text{Moles of titanium chloride}=\frac{95g}{189.7g/mol}=0.517mol$

The chemical equation for the reaction of titanium chloride and sodium follows:

$TiCl_4+4Na\rightarrow 4NaCl+Ti$

By Stoichiometry of the reaction:

1 mole of titanium chloride reacts with 4 moles of sodium

So, 0.517 moles of titanium chloride will react with = $\frac{4}{1}\times 0.517=2.068mol$ of sodium

Now, calculating the mass of sodium from equation 1, we get:

Molar mass of sodium = 23 g/mol

Moles of sodium = 2.068 moles

Putting values in equation 1, we get:

$2.068mol=\frac{\text{Mass of sodium}}{23g/mol}\\\\\text{Mass of sodium}=(2.068mol\times 23g/mol)=47.56g$

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