Question

What mass of solid agcl is obltained when 25 ml of o.O68 m agno3 reacts with excess of aqueous hcl?

Answer 1

first of all, see reaction between AgNO3 and HCl,

$AgNO_3+HCl\rightarrow AgCl+NaNO_3$

here it is clear that one mole of AgNO3 forms one mole of AgCl.

so, number of mole of AgNO3 = number of mole of AgCl

given, volume of AgNO3 , V = 25ml

and concentration of AgNO3 = 0.068M

so, number of mole of AgNO3 = volume in Litre × concentration

= 25/1000 × 0.068 = 0.0017 mol

hence, mole of AgCl = 0.0017 mol

molar mass of AgCl = 108 + 35.5 = 143.5g/mol

now weight of AgCl = mole of AgCl × molar mass of AgCl

= 0.0017 × 143.5 = 0.24395g

hence, required answer is 0.24395g

Answer 2

Answer: 0.24395gm

Explanation: in the image

Hope it's help you