Question

What mass of water is required to react completely with 157.35 g CO2? (Molar mass of H2O = 18.02 g/mol; molar mass of CO2 = 44.01 g/mol)

Answer 1

Answer:

You must use 64.43 g H₂O.

Balanced chemical equation: H₂O + CO₂ → H₂CO₃

Moles of CO₂ = 157.35 g CO₂ × (1 mol CO₂/44.01 g CO₂) = 3.5753 mol CO₂

Moles of H₂O = 3.5753 mol CO₂ × (1 mol H₂O/1 mol CO₂) = 3.5753 mol Fe

Mass of H₂O = 3.5753 mol H₂O × (18.02 g H₂O /1 mol H₂O) = 64.43 g H₂O