what must be added 2x²-3xy+5y² to get x²-xy-y²
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Let p should be add to 2x^2-3xy+5y^2 to get x^2-xy-y^2
(2x^2-3xy+5y^2)+p=x^2-xy-y^2
Therefore
P=x^2-xy-y^2-(2x^2-3xy+5y^2)
=x^2-xy-y^2-2x^2+3xy-5y^2
=-x^2+2xy-6y^2
(2x^2-3xy+5y^2)+p=x^2-xy-y^2
Therefore
P=x^2-xy-y^2-(2x^2-3xy+5y^2)
=x^2-xy-y^2-2x^2+3xy-5y^2
=-x^2+2xy-6y^2
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