what must be added to 12x3+4x2+3x+7 to make the
sum x3+2x2-3x+2
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Let ‘E’ be the required expression. Thus, we have 12x3 – 4x2 + 3x – 7 + E = x3 + 2x2 – 3x + 2 Therefore, E = (x3 + 2x2 – 3x + 2) – (12x3 – 4x2 + 3x – 7) = x3 + 2x2 – 3x + 2 – 12x3 + 4x2 – 3x + 7 Collecting positive and negative like terms together, we get = x3– 12x3+ 2x2 + 4x2 – 3x – 3x + 2 + 7 = – 11x3 + 6x2 – 6x + 9
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