Question

What must be added to 5x³-2x²+6x +7 to make the sum x³+3x³-x+1

Answer 1

Answer:

Step-by-step explanation:

Let the "Interger" or "Equation " be "z", which is added in the Eq (5x^3 – 2x^2 + 6x + 7) to make the sum (x^3 + 3x^2 – x + 1).

A.T.Q.

=)(5x^3 – 2x^2 + 6x + 7) + z = (x^3 + 3x^2 – x + 1)

=) z = (x^3 + 3x^2 – x + 1) - (5x^3 – 2x^2 + 6x + 7)

=) z = x^3 + 3x^2 -x + 1 - 5x^3 + 2x^2 - 6x - 7

=) z = ( x^3 - 5x^3) + ( 3x^2 + 2x^2) + ( -x -6x) + ( 1 - 7)

=) z = - 4x^3 + 5x^2 - 7x - 6

Hence,

If ( - 4x^3 + 5x^2 - 7x - 6) is added to (5x^3 – 2x^2 + 6x + 7). The Sum will be equal to (x^3 + 3x^2 – x + 1).

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Answer 2

Answer:

Step-by-step explanation:

:

Therefore:

5x^3 - 2x^2 + 6x +7 + y = x^3 + 3x^2 - x + 1

Step 1: Rearrange equation and solve for y

y = x^3 + 3x^2 - x + 1 - (5x^3 - 2x^2 + 6x +7)

Step 2: Carry out multiplication of -1

y = x^3 + 3x^2 - x + 1 - (5x^3 - 2x^2 + 6x +7)

y = x^3 + 3x^2 - x + 1 - 5x^3 + 2x^2 - 6x - 7

Step 3: Rearrange equation

y = x^3 - 5x^3 + 3x^2 + 2x^2 -x - 6x + 1 -7

Step 4: Simplify equation by

y = (1 - 5)x^3 + (3 + 2)x^2 + (-1 -6)x + (1–7)

y = -4x^3 + 5x^2 - 7x -6

Therefore, if you add -4x^3 + 5x^2 - 7x -6 to 5x^3 - 2x^2 + 6x +7, you'll get x^3 + 3x^2 -x +1.