Math, asked by gaurtradersdl, 3 months ago

What must be added to each of the numbers 10, 17, 24 and 38, to get the numbers which are in
proportion?​

Answers

Answered by s14648anisha00929
2

Answer:

You can write a proportion. If we let x = the number that should be added, then we can write: (6 + x)/(14 + x) = (18 + x)/(38 + x). If we cross multiply, we get the equation (6 + x)(38 + x) = (14 + x)(18 + x). FOILING each side of the last equation, we get 228 + 44x + x squared (that is, x times x) = 252 + 32x +x squared. If we subtract x squared from each side, we have 228 + 44x = 252 + 32x. Now subtract 32x from each side, we get 228 + 12x = 252. Next, subtract 228 from each side of this last equation and get 12x = 24. Finally, divide both sides by 12 to get x = 2.

Check: Adding 2 to each of the original numbers, we get 8, 16, 20, and 40. These numbers are proportional since 8/16 = 20/40 (each of these ratios are equal to 1/2).

Answered by archanarai68100
0

Step-by-step explanation:

4.3/5. 12. 31shivani. Ace. 366 answers. 147.6K people helped. Let the number added be x. As the numbers are in proportion, 10+ ...

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