what must be added to each term of the ratio 49 : 68, so that it becomes 3 : 4?
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Now according to the question condition,
(49 + x )/(68 + x )= 3/4
Multiple to ecah other we get,
4(49 + x ) = 3(68 + x )
4 × 49 + 4x = 3 × 68 + 3x
4x - 3x = 204 - 196
x = 8 is the right and final answer.
Now put the value of x in above given condition.
(49 + x )/(68 + x )= 3/4
(49 + 8 )/ (68 + 8) = 3/4
57 / 76 = 3/4
3/4 = 3/4
L.H.S. = R.H.S.
I hope that your doubt will be cleared up my dear friend.
Thankyou
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