Question

What must be added to x^3-3x^2-12x+19so that the result is excatly divisible by x^2+x-6

Answer 1

x² + x -6 ) x³ - 3x² -12x  + 19 ( x -4
                x³ + x² -6x
    --------------------------------
              -4x² -6x + 19 
              -4x²-4x + 24 
-------------------------------------
                   -2x - 5 

hence ,
   x³ - 3x² -12x + 19 = (x² +x - 6)(x - 4) -(2x + 5)
   x³ - 3x² -12x + 19 + (2x + 5)  = (x² + x - 6)(x - 4)

hence if we add (2x + 5) 

Answer 2

Answer:

Step-by-step explanation:

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Secondary SchoolMath 5+3 pts

What must be added to x cube minus 3 x square - 12 x + 19 so that the result is exactly divisible by x^2 + X - 6?

Answers

Adityajaiswalrnkt · Ambitious

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THE BRAINLIEST ANSWER!

divide x^3-3x^2-12x+19 by x^2+x-6

multiple x^2 with x so that you can get x^3

which is = x^3 + x^2 - 6x

then change the sign = -x^3 - x^2 + 6x

now cancel x^3 and

sum up the numbers , you will be getting

-4x^2 -6x +19

multiple the divisor with -4

-4x^2 - 4x + 24 , Change the signs

+4x^2 +4x -24 , +4x^2 & -4x^2 will be cancelled

leaving with -2x -5

Take common -

So,-(2x+5)

Hence 2x+5 is your answer

Thank you

this looks a bit mess so just try on a sheet of paper to understand better and maths is all about doing...!