What must be added to x^3-5x^2+7x-1 so as to make x-3 one of its factors ?
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Answer:
-29 needs to be added
hope this helps!
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Step-by-step explanation:
let x-3 be x=3
f(x) =x^3-5x^2+7x-1
f(3) =(3)^3-5(3)^2+7(3)-1
=27-45+21-1
= -18+21-1
=3-1
=2
Hence 2 should be adedd
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