Question

what must be added to x²+5x-6, to get x³-2x²+4x-5?​

Answer 1

GIVEN:

• x² + 5x - 6

TO FIND:

• The no. we have to add to x² + 5x - 6 to get x³ - 2x² + 4x - 5

SOLUTION:

Let, assume that we add, r(x)

we know, that

p(x) + r(x) = q(x)

where,

• p(x) = x² + 5x - 6
• q(x) = x³ - 2x² + 4x - 5

substituting these values in formula we got,

$\bold{ \to p(x) + r(x) = q(x)}$

$\bold{ \to {x}^{2} + 5x - 6+ r(x) = {x}^{3} - 2 {x}^{2} + 4x - 5}$

$\bold{ \to r(x) = {x}^{3} - 2 {x}^{2} + 4x - 5 -{x}^{2} - 5x + 6}$

simplify it, we get

$\bold{ \to r(x) = {x}^{3} - 3 {x}^{2} - x + 1 }$

Hence, x³ - 3x² - x + 1 will be added to x² + 5x - 6 to get x³ - 2x² + 4x - 5.

Answer 2

Answer:

Step-by-step explanation:

x³ - 3x² - x + 1