What must be added to x³ - 3x² - 12x + 19 so that the result is exactly divisible by x² + x - 6 ?
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Answer:
x^3+x^2-6x. -4x^2-6x+19. -4x^2-4x+24
2x+5
Divide x^3-3x^2-12x+19 by x^2+x-6
You get reminder -2x -5
So if you add 2x + 5 it will be exactly divisible
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