Math, asked by Shub18nov, 10 months ago

what must be added to y cube minus y squared minus 3 Y - 22 get a square minus 5 Y + 6 ​

Answers

Answered by MaheswariS
0

\textsf{Let f(y)=}\mathsf{y^3-y^2-3y-22}

\textsf{Let g(y) be the required polynomial to be added to get}\mathsf{\;\;y^2-5y+6}

\textsf{As per given data,}

\mathsf{f(y)+g(y)=y^2-5y+6}

\implies\mathsf{y^3-y^2-3y-22+g(y)=y^2-5y+6}

\implies\mathsf{g(y)=y^2-5y+6-(y^3-y^2-3y-22)}

\implies\mathsf{g(y)=y^2-5y+6-y^3+y^2+3y+22}

\implies\boxed{\mathsf{g(y)=-y^3+2y^2-2y+28}}

\therefore\textsf{We must be add $-y^3+2y^2-2y+28$}

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