Question

what must be subracted from the polynomial p(x)=x^cube +13x^square+35x+25.so that the resulting polynomial is exactly divisible by g(x)=x^square +
11x+10

Answer 1

I hope this Will help you

Answer 2

Answer:

3x+5

Step-by-step explanation:

Dividend = $x^3 +13x^2+35x+25$

Divisor = $x^2+11x+10$

$Dividend = (Divisor \times Quotient )+Remainder$

$x^3 +13x^2+35x+25 = (x^2+11x+10 \times (x+2) )+(3x+5)$

So, Remainder = 3x+5

So, 3x+5  must be subtracted from the$x^3 +13x^2+35x+25$so that the resulting polynomial is exactly divisible by $x^2+11x+10$