What must be subtracted from 3a2-6ab-3b2-1 to get 4a2-7ab-4b2+1?
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Answer:
- a² + ab + b² - 2
Step-by-step explanation:
Let X be the number to be subtracted.
=> [3a² - 6ab - 3b² - 1 ] - X = 4a² - 7ab - 4b² + 1
=> X = [3a² - 6ab - 3b² - 1 ] - [4a² - 7ab - 4b² + 1]
= 3a² - 4a² - 6ab + 7ab - 3b² + 4b² - 1 - 1
= - a² + ab + b² - 2
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