Question

what must be subtracted from a3 - 4a2 + 6 to abtain a2 - 2a + 1 ?​

Answer 1

Answer:

^_^_^_^_^_^

Let x should be subtracted,

a^3 - 4a^2 + 5a - 6 - x = a^2 - 2a + 1

=> a^3 - 4a^2 + 5a - 6 - a^2 + 2a - 1 = x

=> a^3 - 4a^2 - a^2 + 5a + 2a - 6 - 1 = x

=> a^3 - 5a^2 + 7a - 7 = x

Hence. a^3 - 5a^2 + 7a - 7 should be subtracted.

Answer 2

Step-by-step explanation:

let the number be x

a3-4a2+6-x=a2-2a+1

-x=(a2-2a+1) -(a3-4a2+6)

-x=a-2a+5

so the number is a-2a+5