Math, asked by rani678132, 4 months ago

what must be subtracted from a³b+6a²b²-7ab+4 to get -7a²b²+2a³b+6ab-1

Answers

Answered by gopalpvr

10

Answer:

- a³b + 13 a²b² - 13ab + 5

Step-by-step explanation:

what must be subtracted from a³b+6a²b²-7ab+4 to get -7a²b²+2a³b+6ab-1

ans)

required expression = a³b+6a²b²-7ab+4 -(-7a²b²+2a³b+6ab-1)

= a³b+6a²b²-7ab+4 +7a²b²-2a³b - 6ab + 1

= - a³b + 13 a²b² - 13ab + 5

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