Question

What must be subtracted from each term of the ratio 68:49 so that it becomes 3:4?

Answer 1

Thanks for asking the question!

ANSWER::

Let the subtracted term be x/y
So, 68/49 - x/y = 3/4


-x/y = 3/4 - 68/49
-x/y = (147-272)/196

-x/y = -125/196 

x/y = 125/196  is the term which when subtracted from 68/49 gives 3/4.
Verification :-
68/49 - 125/196

13328-6125/9604
7203/9604

1029/1372  (Reduced by 7)

147/196  (Reduced by 7)

21/28   (Reduced by 7)

3/4      (Reduced by 7)

Hope it helps!

Answer 2

$\huge{\mathecal\underline{Answer:}}}$

Let X be subtracted from each term of the ratio 68 : 49 respectively.

$\underline{\bold{Given:-}}$

$\frac{68 - x}{49 - x} = \frac{3}{4} \\ \\ 4(68 - x) = 3(49 - x) \\ \\ 272 - 4x = 147 - 3x \\ \\ 272 - 147 = 4x - 3x \\ \\ 125 = x \\ \\ x = 125$

So, X must be subtracted from each term of the ratio 68:49 so that it becomes 3:4.