What must be subtracted from? y4+2y2-3y+7 to get y3+y2+y-1?
1.y4-y3+y2-4y+8
2.y4+y3+y2-4y+8
3.y3-y2+2y+8
4.y4-y3+y2+4y+8
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Answer:
Adding the given terms, we have
(i) 7abc + (- 5abc) + (9 abc) + (- 8abc)
= 7abc - 5abc + 9abc - 8abc
= (7 - 5 + 9 - 8)abc
= (16 - 13)abc
= 3abc
(ii) 2x2y + (- 4x2y) + 6x2y + (- 5x2y)
= 2x2y - 4x2y + 6x2y - 5x2y
= (2 - 4 + 6 - 5)x2y
= (8 - 9)x2y
= -x2y
Step-by-step explanation:
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