Question

what must be the dimensions of a rectangle having an area of 125m2 and perimeter of 60m?

Answer 1

Step-by-step explanation:

we know that;

area of rectangle = length*width;

Perimeter = 2(length+width);

Now putting the value of area and perimeter in above equations;

we get

125 = L*W;

60 = 2(L+W);

30 = L+W;

L = 30-W; putting this value in 125 = L*W;

125 = (30-W) W;

Solving this equation;

W2-30W +125 = 0;

we get W is equal to 25 and 5;

case 1. If width is 25 then length is = 30-25 = 5m;

case 2. If width is 5 then length is = 30-5 = 25m;