What must be the value of k so that 5k - 3, k + 8, and 3k - 11 will form an arithmetic sequence?
Answers
Answered by
1
In A.P.,
Middle term=(Sum of first term + last term)/2
k + 8 = (5k-3 + 3k-11)/2
k+8=(8k-14)/2
k+8=4k-7
k=5
Middle term=(Sum of first term + last term)/2
k + 8 = (5k-3 + 3k-11)/2
k+8=(8k-14)/2
k+8=4k-7
k=5
Answered by
0
Hey there !!!!
5k-3 ,k+8 , 3k-11 will form an arithmetic sequence only when
2(k+8) = 5k-3+3k-11
2k+16=8k-14
-6k=-30
-k=-5
k=5
5k-3 ,k+8 , 3k-11 will form an arithmetic sequence only when
2(k+8) = 5k-3+3k-11
2k+16=8k-14
-6k=-30
-k=-5
k=5
Similar questions