What no.must be added to each term of the ratio 7:5 so that the ratio becomes 5:4
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Concept:
A ratio is a fraction which indicates how many times one quantity contains as compared to the other quantity. If it is represented in the form a:b, it indicates fraction a/b where first term acts as numerator and second term as denominator.
Given:
ratio of the form a:b given as 7:5
Find:
what must be added to the ratio 7:5 to make it 5:4
Solution:
Let the quantity to be added be 'x'
Now, By considering the given data,
the equation becomes
(7+x):(5+x)=5:4 which is
(7+x)/(5+x)=5/4
therefore, by cross multiplying the equation becomes
4*(7+x) =5*(5+x)
28 + 4x = 25 +5x
28-25 =5x-4x
3 = x
therefore x=3
Hence 3 must be added to both terms in 7:5 to make it 5:4
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