Math, asked by yagyansh24, 11 months ago

what number must be added to each of the number 10,18 ,22,38 so that they form a propotion​


drithvik1: well i never tryed these questions

Answers

Answered by rathibhagwati3
6

Answer:

Step-by-step explanation:

=) Let the number is added be x .

Given , Sequence = 10 , 18 , 22 , 38 .

So ,

=) 1st term = 10 .

=) 2nd term = 18 .

=) 3rd term = 22 .

=) 4th term = 38 .

We know ,

(term 1 + x) / (term 2 + x) = (term 3 + x) / term 4 + x)

Now , putting the values .

=) (10 + x) / (18 + x) = (22 + x) / (38 + x)

=) (10 + x) (38 + x) = (18 + x) (22 + x)

=) 380 + 10x + 38x + x² = 396 + 18x + 22x + x²

=) 380 + 48x + x²= 396 + 40x + x²

=) 48x - 40x = 396 - 380

=) 8x = 16

=) x = 16/8

=) x = 2. (ans.)

Hence , the number is added should be 2 .

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