Math, asked by asgaraliasgar37, 2 months ago


What number must be added to each of the numbers 2, 3, 6, 8 to get the numbers which are
in proportion?

Answers

Answered by amitsharma777222999
5

Step-by-step explanation:

2+x/3+x=6+x/8+x

(2+x)(8+x)=(3+x)(6+x)

16+10x+x^2=18+9x+x^2

10x-9x=18-16

x=2

Similar questions