Math, asked by urvashi99, 10 months ago

what number must be subtracted from each 9 11 15 and 19 so that the difference will be in proportion​

Answers

Answered by rachanamacha8
11

Answer:

answer is 3

Step-by-step explanation:

9-x : 11-x::15-x : 19-x

9-x *19-x= 11-x *15-x

171-19x+x square-9x=-11x+165-15x+x square

171-28x= -26x+165

2x=6

x=3


urvashi99: thnx
Answered by pinquancaro
7

The difference will be in proportion​ 3.

Step-by-step explanation:

To find : What number must be subtracted from each 9, 11, 15 and 19 so that the difference will be in proportion​ ?

Solution :

Let the number be 'x'.

Number must be subtracted from each 9, 11, 15 and 19 so that the difference will be in proportion​

i.e. 9-x : 11-x::15-x : 19-x

So, \frac{9-x}{11-x} =\frac{15-x}{19-x}

Cross multiply,

(9-x)(19-x)=(15-x)(11-x)

171-19x+x^2-9x=-11x+165-15x+x^2

171-28x=-26x+165

2x=6

x=3

The difference will be in proportion​ 3.

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