what number must be subtracted from each of the number 27 ,38, 7,8 so that the remainder at the proportion
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3
number 7 ....
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Answered by
7
let the no subtracted be x
according to the question
27-x : 38 - x : : 7 - x : 8 - x
= > (27 - x) ( 8 - x) = ( 7-x) ( 38-x)
= > 216 - 27x - 8x + x^2 = 266 - 7x - 38x + x^2
=> 216 - 35x = 266 - 45x
=> 45x - 35x = 266 - 216
=> 10 x = 50
=> x = 5.....
5 will be subtracted....
according to the question
27-x : 38 - x : : 7 - x : 8 - x
= > (27 - x) ( 8 - x) = ( 7-x) ( 38-x)
= > 216 - 27x - 8x + x^2 = 266 - 7x - 38x + x^2
=> 216 - 35x = 266 - 45x
=> 45x - 35x = 266 - 216
=> 10 x = 50
=> x = 5.....
5 will be subtracted....
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