Question

what number must be subtracted from each of the number 27 ,38, 7,8 so that the remainder at the proportion

Answer 1

let the no. to be subtracted be x
A/Q
(27-x) = (7-x)
---------- --------
(38-x) (8-x)

=>(27-x) (8-x)=(38-x) (7-x)
=>27 (8-x) -x (8-x)=38 (7-x)-x (7-x)
=>216-27x-8x-x^2=266-38x-7x-x^2
=>216-35x-x^2=266-45x-x^2
=>-35x+45x-x^2+x^2=266-216
=>10x=50
=>x=50÷10
=>x=5
The no. to be subtracted so that the given nimbers are in proportion is 5.