What number should be added or subtracted from each term in the ratio 11:9 so that it become 6:5
Answers
Therefore equation will be
11+x / 9+x = 6/5
Cross multiply
5*( 11+x) = 6*(9+x)
55 + 5x = 54 + 6x
X = 1
Similar in case of subtract ion
1 Should be added to each term of 11 : 9 so that it becomes 6:5
Step-by-step explanation:
Let say number Should be added = X in each term of 11 : 9 so that it becomes 6 : 5
=> 11 + X : 9 + X = 6 : 5
=> (11 + X) / (9 + X) = 6/5
=> 5 (11 + X) = 6( 9 + X)
=> 55 + 5X = 54 + 6X
=> 1 = X
=> X = 1
1 Should be added to each term of 11 : 9 so that it becomes 6:5
Let say Y should be subtracted in each term of 11 : 9 so that it becomes 6 : 5
=> (11 - Y)/(9 - Y) = 6/5
=> 55 - 5Y = 54 - 6Y
=> Y = - 1
-1 should be subtracted in each term of 11 : 9 so that it becomes 6 : 5
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