Question

what number should be added to 2x^3-3x^2-8x+2 so that the resulting polynomial is a factor of x+3​

Answer 1

If (x+3) is a factor of the equation $2x^3-3x^2-8x+2$, then on substituting x with (-3), we will get the anwser 0.

Substituting x = -3

$2x^3-3x^2-8x+2$

$=2(-3)^3-3(-3)^2-8(-3)+2$

$=2(-27)-3(9)+24+2$

$=-54-27+24+2$

$=-55$

We can see that we are not getting zero.

So, if we add 55 to the given equation, we will get zero.

Hence, 55 should be added to the polynomial.