What number should be added to 3x^3-5x^2+6x so that when resulting polynomial is divided by (x-3) , the remainder is 8.
Answers
Answered by
20
x-3=0
x=3
let the number be added is y
3(3)³ -5(3)²+6(3)+y=8
81-45+18+y=8
54+y=8
y=8-54
y=-46
x=3
let the number be added is y
3(3)³ -5(3)²+6(3)+y=8
81-45+18+y=8
54+y=8
y=8-54
y=-46
Answered by
1
Answer:
- 46
Step-by-step explanation:
3x^3-5x^2+6x = f(x)
remainder is 8
x-3=0
x=3+0
x = 3
Let the number to be added be y
f ( 3) = 3 () - 5 () + 6 ( 3 ) + y = 8
= 81 -45 + 18 - 8 + y = 0
= 46 + y = 0
y = - 46
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