Math, asked by amanjyotishi, 1 year ago

What number should be added to 3x^3-5x^2+6x so that when resulting polynomial is divided by (x-3) , the remainder is 8.

Answers

Answered by kondurusai
20
x-3=0
x=3
let the number be added is y
3(3)³ -5(3)²+6(3)+y=8
81-45+18+y=8
54+y=8
y=8-54
y=-46
Answered by jbaruni
1

Answer:

- 46

Step-by-step explanation:

3x^3-5x^2+6x = f(x)

remainder is 8

x-3=0

x=3+0

x = 3

Let the number to be added be y

f ( 3) =  3 (3^{3}) - 5 (3^{2}) + 6 ( 3 ) + y =  8

= 81 -45 + 18 - 8 + y = 0

= 46 + y = 0

y = - 46

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