Question

what number should be added to each of the numbers 8 15 18 and 30 such that the resulting number are in the proportions​

Answer 1

see the attachment for answers

$\boxed{ \mathcal{ \orange{JAI }\: {HIND } \: \blue{JAI} \: \green{ BHARAT}}}$

Answer 2

Answer:

Let the number must be added be x, then the new number = 6 + x, 15 + x, 20 + x, 43 + x

... These are proportionals. 6 + X: 15+X:: 20 + x: 43+ X

or (6 + x)(43 + x) = (15 + x)(20 + x) or 49x - 35x = 300 - 258

or 258 + 6x + 43x + x² = 300 + 20x + 15x + x²

or 14x = 42

or x = 3.

Step-by-step explanation:

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