Question

what number should be added to x square+6x to get [x+3] square?​

Answer 1

Answer:

9 should be added to x^2+6x to get (x+3)^2

Step-by-step explanation:

let the unknown number be k.

x^2+6x+k = (x+3)^2

x^2+6x+k = x^2+6x+9

compare the constant term on both sides,we get k=9

the number is 9